The two methyl groups are cis to one another in the E
isomer, but trans to one another in the Z isomer. Hence A
is the E isomer since there is a larger nOe between the methyl groups
in this case, indicating that they are closer together than in isomer B.
back to simple answer to question 5
back to CHAPTER 2 answers
back to answers to problems back to STEREOCHEMISTRY home page