CHAPTER 3: Question 12
3D explanations
Consider first the stereocentre at the molybdenum atom on the left as drawn.
The six ligands around this stereocentre are first ranked into an order
of priority (1-6) using the CIP rules. Rule 1 is sufficient to allow the
chlorine atom to be ranked 1, sulfur 2, phosphorus 3, and the nitrogen
4. The other two ligands both start with a carbon atom but are distinguished
by CIP rule 2, allowing the C=O group to be ranked 5 and the butyne 6.
Next, a principal axis is defined, as the axis containing the ligand ranked
1 and the molybdenum atom. This is shown in red in the diagram below. Next,
the molecule is viewed along the principal axis with the atom ranked 1
towards the viewer. The rotatable 3D structure may aid in visualizing this
rotation. The three highest ranked ligands in the plane perpendicular to
the principal axis are seen to decrease in priority in an anti-clockwise
direction, so this stereocentre has the (A)-configuration.
The process is then repeated for the other molybdenum atom. Since the
same six ligands are present, the ranking order and principal axis will
be as above. In this case however, when the molecule is viewed along the
principal axis with the ligand of highest priority at the front, then the
three highest ranked ligands in the plane perpendicular to the principal
axis are seen to decrease in priority in a clockwise direction. The rotatable
3D structure may aid in visualizing this rotation (note the phenyl groups
have been replaced by hydrogen for clafity, and the butyne ligands have
been replaced by fluorines). Hence, this stereocentre has the (C)-configuration.
back to simple answer to question 12
back to CHAPTER 3 answers
back to answers to problems
back to STEREOCHEMISTRY home page