
|
|
|
|
Structure drawn in text Isomer A Isomer B
R
S
R
R
S
S
From the table, it is apparent that isomer A is the enantiomer of the structure given in the text since it has the opposite absolute configuration at both stereocentres. Isomer B is a diastereomer of both isomer A and the isomer in the text, since it has the same configuration at one stereocentre but the opposite configuration at the other stereocentre. Isomer B is a meso compound since it contains two stereocentres with the same substituents attached to each, but with opposite absolute configurations.
Enantiomers have identical physical properties except for the sign of their specific rotations. Thus, isomer A will have the same melting point (170-172oC) as the isomer in the text, and will have a specific rotation of -12.4. Isomer B is a meso compound and so is achiral and will have a specific rotation of 0. The melting point of this isomer cannot be predicted from the information given, since it is a diastereomer of the isomer in the text and diastereomers have different physical properties.
The isomer in the text is the l-isomer, since the two stereocentres both have the same (R) absolute configuration. Similarly, isomer A is the l-isomer, since the two stereocentres both have the same (S) absolute configuration. Isomer B however is the u-diastereomer since one stereocentre has the (R)-configuration whilst the other has the (S)-configuration. To assign the stereochemistry using the syn / anti nomenclature, the compounds must be drawn in flying wedge projections. The structure in the text is already drawn in this way, as are the two diagrams of isomers A and B shown above. For the isomer in the text, the two non-hydrogen substituents attached to the main carbon chain at the two stereocentres are on the same side of the molecule (these are the two OH groups and are both drawn with hashed bonds). Hence, this is the syn-isomer. Similarly, for isomer A, the two non-hydrogen substituents attached to the main carbon chain at the two stereocentres are on the same side of the molecule. Hence, this is also the syn-isomer. For isomer B however, the two substituents are on opposite sides of the molecule, so this is the anti-isomer. To assign the stereochemistry using the erythro / threo nomenclature, the compounds must first be converted into Fischer projections as shown below. (The 3D structures above may be helpful in carrying out these rotations) Thus the structures are rotated until all vertical bonds are pointing away from the viewer and all horizontal bonds towards the viewer. All wedges and hashes are then replaced by normal bonds and bonds to hydrogen atoms are deleted. For the isomer in the text, and isomer A, the two OH groups are on opposite sides of the Fischer projection, so this is the threo-isomer whilst for isomer B, the two OH groups are on the same side of the projection so this is the erythro-isomer.

back to simple answer to question 5 back to CHAPTER 4 answers
back to answers to problems back to STEREOCHEMISTRY home page